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explicitly show each die roll

This commit is contained in:
Patrick Hurst 2010-08-17 13:00:41 -04:00
parent 7876fd57ac
commit b70c703af5
1 changed files with 16 additions and 15 deletions
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31
plugins/dice.py
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@ -17,17 +17,19 @@ split_re = re.compile(r'([\d+-]*)d?(F|\d*)', re.I)
def nrolls(count, n):
"roll an n-sided die count times"
if n == "F":
return [random.randint(-1,1) for x in xrange(count)]
if n < 2: # it's a coin
if count < 5000:
return sum(random.randint(0, 1) for x in xrange(count))
return [random.randint(0, 1) for x in xrange(count)]
else: # fake it
return int(random.normalvariate(.5*count, (.75*count)**.5))
return [int(random.normalvariate(.5*count, (.75*count)**.5))]
else:
if count < 5000:
return sum(random.randint(1, n) for x in xrange(count))
return [random.randint(1, n) for x in xrange(count)]
else: # fake it
return int(random.normalvariate(.5*(1+n)*count,
(((n+1)*(2*n+1)/6.-(.5*(1+n))**2)*count)**.5))
return [int(random.normalvariate(.5*(1+n)*count,
(((n+1)*(2*n+1)/6.-(.5*(1+n))**2)*count)**.5))]
@hook.command('roll')
@ -46,26 +48,25 @@ def dice(inp):
spec = whitespace_re.sub('', inp)
if not valid_diceroll_re.match(spec):
return "Invalid diceroll"
sum = 0
groups = sign_re.findall(spec)
rolls = []
bias = 0
for roll in groups:
count, side = split_re.match(roll).groups()
count = int(count) if count not in " +-" else 1
if side.lower() == "f":
if count > 0:
sum += nrolls(count, 3) - 2 * count
else:
sum -= nrolls(count, 3) + 2 * count
if side.lower() == "f": # fudge dice are basically 1d3-2
rolls += nrolls(count, "F")
elif side == "":
sum += count
bias += count
else:
side = int(side)
try:
if count > 0:
sum += nrolls(count, side)
rolls += nrolls(count, side)
else:
sum -= nrolls(abs(count), side)
rolls += [-x for x in nrolls(abs(count), side)]
except OverflowError:
return "Thanks for overflowing a float, jerk >:["
return "%s: %d" % (desc, sum)
return "%s: %d (%s=%s)" % (desc, sum(rolls)+bias, inp, str(rolls).strip("[]"))