Auto merge of #188 - koverstreet:master, r=cuviper
bigint: Fix calculation of size for multiply temporaries When x.len() and y.len() are both equal and odd, we have x1.len() + y1.len() + 1 (the required size to multiply x1 and y1) > y.len() + 1 This fixes #187
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@ -991,9 +991,11 @@ fn mac3(acc: &mut [BigDigit], b: &[BigDigit], c: &[BigDigit]) {
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let (x0, x1) = x.split_at(b);
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let (y0, y1) = y.split_at(b);
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/* We reuse the same BigUint for all the intermediate multiplies: */
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let len = y.len() + 1;
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/*
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* We reuse the same BigUint for all the intermediate multiplies and have to size p
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* appropriately here: x1.len() >= x0.len and y1.len() >= y0.len():
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*/
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let len = x1.len() + y1.len() + 1;
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let mut p = BigUint { data: vec![0; len] };
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// p2 = x1 * y1
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@ -3827,6 +3829,15 @@ mod biguint_tests {
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}
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}
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#[test]
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fn test_mul_overflow() {
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/* Test for issue #187 - overflow due to mac3 incorrectly sizing temporary */
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let s = "531137992816767098689588206552468627329593117727031923199444138200403559860852242739162502232636710047537552105951370000796528760829212940754539968588340162273730474622005920097370111";
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let a: BigUint = s.parse().unwrap();
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let b = a.clone();
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let _ = a.checked_mul(&b);
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}
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#[test]
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fn test_checked_div() {
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for elm in MUL_TRIPLES.iter() {
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